(z/(z-1))+(3/(z+1))=(2/(z^2-1))

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Solution for (z/(z-1))+(3/(z+1))=(2/(z^2-1)) equation:


D( z )

z-1 = 0

z+1 = 0

z^2-1 = 0

z-1 = 0

z-1 = 0

z-1 = 0 // + 1

z = 1

z+1 = 0

z+1 = 0

z+1 = 0 // - 1

z = -1

z^2-1 = 0

z^2-1 = 0

1*z^2 = 1 // : 1

z^2 = 1

z^2 = 1 // ^ 1/2

abs(z) = 1

z = 1 or z = -1

z in (-oo:-1) U (-1:1) U (1:+oo)

z/(z-1)+3/(z+1) = 2/(z^2-1) // - 2/(z^2-1)

z/(z-1)+3/(z+1)-(2/(z^2-1)) = 0

z/(z-1)+3/(z+1)-2*(z^2-1)^-1 = 0

z/(z-1)+3/(z+1)-2/(z^2-1) = 0

(z*(z+1)*(z^2-1))/((z-1)*(z+1)*(z^2-1))+(3*(z-1)*(z^2-1))/((z-1)*(z+1)*(z^2-1))+(-2*(z-1)*(z+1))/((z-1)*(z+1)*(z^2-1)) = 0

z*(z+1)*(z^2-1)+3*(z-1)*(z^2-1)-2*(z-1)*(z+1) = 0

z^4+4*z^3-4*z^2-2*z^2-4*z+2+3 = 0

z^4+4*z^3-6*z^2-4*z+5 = 0

z^4+4*z^3-6*z^2-4*z+5 = 0

z^4+4*z^3-6*z^2-4*z+5 = 0

{ 1, -1, 5, -5 }

1

z = 1

z^4+4*z^3-6*z^2-4*z+5 = 0

1

z-1

z^3+5*z^2-z-5

z^4+4*z^3-6*z^2-4*z+5

z-1

z^3-z^4

5*z^3-6*z^2-4*z+5

5*z^2-5*z^3

5-z^2-4*z

z^2-z

5-5*z

5*z-5

0

z^3+5*z^2-z-5 = 0

{ 1, -1, 5, -5 }

1

z = 1

z^3+5*z^2-z-5 = 0

1

z-1

z^2+6*z+5

z^3+5*z^2-z-5

z-1

z^2-z^3

6*z^2-z-5

6*z-6*z^2

5*z-5

5-5*z

0

z^2+6*z+5 = 0

DELTA = 6^2-(1*4*5)

DELTA = 16

DELTA > 0

z = (16^(1/2)-6)/(1*2) or z = (-16^(1/2)-6)/(1*2)

z = -1 or z = -5

z in { -5, -1, 1, 1}

(z+5)*(z+1)*(z-1)^2 = 0

((z+5)*(z+1)*(z-1)^2)/((z-1)*(z+1)*(z^2-1)) = 0

((z+5)*(z+1)*(z-1)^2)/((z-1)*(z+1)*(z^2-1)) = 0 // * (z-1)*(z+1)*(z^2-1)

(z+5)*(z+1)*(z-1)^2 = 0

( z+1 )

z+1 = 0 // - 1

z = -1

( z+5 )

z+5 = 0 // - 5

z = -5

( z-1 )

z-1 = 0 // + 1

z = 1

z in { -1}

z in { 1}

z = -5

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